NEET 2023 | Motion in a Plane Question 6 | Physics

A horizontal bridge is built across a river. A student standing on the bridge throws a small ball vertically upwards with a velocity $$4 \mathrm{~m} \mathrm{~s}^{-1}$$. The ball strikes the water surface after $$4 \mathrm{~s}$$. The height of bridge above water surface is (Take $$g=10 \mathrm{~m} \mathrm{~s}^{-2}$$ )

60 m

64 m

68 m

56 m

NEET 2022 Phase 2

MCQ (Single Correct Answer)

-1

A cricket ball is thrown by a player at a speed of 20 m/s in a direction 30$$^\circ$$ above the horizontal. The maximum height attained by the ball during its motion is

(g = 10 m/s²)

25 m

5 m

10 m

20 m

NEET 2022 Phase 1

MCQ (Single Correct Answer)

-1

A ball is projected with a velocity, 10 ms^$$-$$1, at an angle of 60$$^\circ$$ with the vertical direction. Its speed at the highest point of its trajectory will be

Zero

5$$\sqrt3$$ ms^$$-$$1

5 ms^$$-$$1

10 ms^$$-$$1

NEET 2021

MCQ (Single Correct Answer)

-1

A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolution.

If this particle were projected with the same speed at an angle '$$\theta$$' to the horizontal, the maximum height attained by it equals 4R. The angle of projection, $$\theta$$, is then given by :

$$\theta = {\sin ^{ - 1}}{\left( {{{2g{T^2}} \over {{\pi ^2}R}}} \right)^{1/2}}$$

$$\theta = {\cos ^{ - 1}}{\left( {{{g{T^2}} \over {{\pi ^2}R}}} \right)^{1/2}}$$

$$\theta = {\cos ^{ - 1}}{\left( {{{{\pi ^2}R} \over {g{T^2}}}} \right)^{1/2}}$$

$$\theta = {\sin ^{ - 1}}{\left( {{{{\pi ^2}R} \over {g{T^2}}}} \right)^{1/2}}$$

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NEET Subjects

Biology

Zoology

Human Health and Diseases Body Fluids and Its Circulation Locomotion and Movement Neural Control and Coordination Reproduction in Organisms Reproductive Health Structural Organisation in Animals Digestion and Absorption Excretory Products and Their Elimination Chemical Coordination and Integration Human Reproduction Animal Kingdom Breathing and Exchange of Gases Evolution