AIPMT 2015 | Atoms and Nuclei Question 40 | Physics

Consider 3^rd orbit of He⁺ (Helium), using non-relativistic approach, the speed of electron in this orbit will be [given K = 9 $$ \times $$ 10⁹ constant, Z = 2 and h (Planck's Constant) = 6.6 $$ \times $$ 10^$$-$$34 J s]

0.73 $$ \times $$ 10⁶ m/s

3.0 $$ \times $$ 10⁸ m/s

2.92 $$ \times $$ 10⁶ m/s

1.46 $$ \times $$ 10⁶ m/s

AIPMT 2015 Cancelled Paper

MCQ (Single Correct Answer)

-1

Out of Syllabus

If radius of the $${}_{13}^{27}$$ Al nucleus is taken to be R_Al, then
the radius of $${}_{53}^{125}$$Te nucleus is nearly

$${3 \over 5}{R_{Al}}$$

$${\left( {{{13} \over {53}}} \right)^{1/3}}{R_{Al}}$$

$${\left( {{{53} \over {13}}} \right)^{1/3}}{R_{Al}}$$

$${5 \over 3}{R_{Al}}$$

AIPMT 2014

MCQ (Single Correct Answer)

-1

Hydrogen atom in ground state is excited by a monochromatic radiation of $$\lambda $$ = 975 $$\mathop A\limits^ \circ $$. Number of spectral lines in the resulting spectrum emitted will be

0 10

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