AIPMT 2015 | Wave Optics Question 25 | Physics

At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between the Huygen's wavelet from the edge of the slit and the wavelet from the midpoint of the slit is

$$\pi $$ radian

$${\pi \over 8}$$ radian

$${\pi \over 4}$$ radian

$${\pi \over 2}$$ radian

AIPMT 2015

MCQ (Single Correct Answer)

-1

Two slits in Young's experiment have widths in the ratio 1 : 25. The ratio of intensity at the maxima and minima in the interference pattern, $${{{I_{max}}} \over {{I_{min}}}}$$ is

$${{49} \over {121}}$$

$${4 \over 9}$$

$${9 \over 4}$$

$${{121} \over {49}}$$

AIPMT 2015 Cancelled Paper

MCQ (Single Correct Answer)

-1

For a parallel beam of monochromatic light of wavelength '$$\lambda $$' , diffraction is produced by a single slit whose width 'a' is of the order of the wavelength of the light. If 'D' is the distance of the screen from the slit, the wifth of the central maxima will be

$${{Da} \over \lambda }$$

$${{2Da} \over \lambda }$$

$${{2D\lambda } \over a}$$

$${{D\lambda } \over a}$$

AIPMT 2015 Cancelled Paper

MCQ (Single Correct Answer)

-1

In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern ?

0.5 mm

0.02 mm

0.2 mm

0.1 mm

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