Electricity
Current Electricity
MCQ (Single Correct Answer)
Moving Charges and Magnetism
MCQ (Single Correct Answer)
Magnetism and Matter
MCQ (Single Correct Answer)
Electromagnetic Induction
MCQ (Single Correct Answer)
Electromagnetic Waves
MCQ (Single Correct Answer)
Modern Physics
Semiconductor Electronics
MCQ (Single Correct Answer)
1
AIPMT 2010 Prelims
MCQ (Single Correct Answer)
+4
-1
Assuming the sun to have a spherical outer surface of radius r, radiating like a black body at temperature toC, the power received by a unit surface, (normal to the incident rays) at a distance R from the centre of the sun is
where $$\sigma $$ is the Stefan's constant.
A
$${{{r^2}\sigma {{\left( {t + 273} \right)}^4}} \over {4\pi {R^2}}}$$
B
$${{16{\pi ^2}{r^2}\sigma {t^4}} \over {{R^2}}}$$
C
$${{{r^2}\sigma {{\left( {t + 273} \right)}^4}} \over {{R^2}}}$$
D
$${{4\pi {r^2}\sigma {t^4}} \over {{R^2}}}$$
2
AIPMT 2010 Prelims
MCQ (Single Correct Answer)
+4
-1
The total radiant energy per unit area, normal to the direction of incidence, received at a distance R from the centre of a star of radius r, whose outer surface radiates as a black body at a temperature TK is given by
A
$${{\sigma {r^2}{T^4}} \over {{R^2}}}$$
B
$${{\sigma {r^2}{T^4}} \over {4\pi {R^2}}}$$
C
$${{\sigma {r^2}{T^4}} \over {{R^4}}}$$
D
$${{4\pi \sigma {r^2}{T^4}} \over {{R^2}}}$$
3
AIPMT 2010 Prelims
MCQ (Single Correct Answer)
+4
-1
A cylindrical metallic rod in thermal contact with two reservoirs of heat at its two ends conducts an amount of heat Q in time t. The metallic rod is melted and the material is formed into a rod of half the radius of the original rod. What is the amount of heat conducted by the new rod, when placed in thermal contact with the two reservoirs in time t?
A
$${Q \over 4}$$
B
$${Q \over {16}}$$
C
2Q
D
$${Q \over 2}$$
4
AIPMT 2009
MCQ (Single Correct Answer)
+4
-1
The two ends of a rod of length L and a uniform cross-sectional area A are Kept at two temperatures T1 and T2 (T1 > T2). The rate of heat transfer, $${{dQ} \over {dt}}$$ through the rod in a steady state is given by :
A
$${{dQ} \over {dt}} = {{k\left( {{T_1} - {T_2}} \right)} \over {LA}}$$
B
$${{dQ} \over {dt}} = kLA({T_1} - {T_2})$$
C
$${{dQ} \over {dt}} = {{kA\left( {{T_1} - {T_2}} \right)} \over L}$$
D
$${{dQ} \over {dt}} = {{kL\left( {{T_1} - {T_2}} \right)} \over A}$$
NEET Subjects