AIPMT 2005 | Electromagnetic Induction Question 26 | Physics

As a result of change in the magnetic flux linked to the closed loop as shown in the figure, an e.m.f. $$V$$ volt is induced in the loop. The work done (joule) in taking a charge Q coulomb once along the loop is

AIPMT 2005 Physics - Electromagnetic Induction Question 12 English

AIPMT 2005 Physics - Electromagnetic Induction Question 12 English

2QV

QV/2

zero

AIPMT 2004

MCQ (Single Correct Answer)

-1

The magnetic flux through a circuit of resistance R changes by an amount $$\Delta $$$$\phi $$ in a time $$\Delta $$t. Then the total quantity of electric charge Q that passes any point in the circuit during the time $$\Delta $$t is represented by

$$Q = {1 \over R}.{{\Delta \phi } \over {\Delta t}}$$

$$Q = {{\Delta \phi } \over R}$$

$$Q = {{\Delta \phi } \over {\Delta t}}$$

$$Q = R.{{\Delta \phi } \over {\Delta t}}$$

AIPMT 2001

MCQ (Single Correct Answer)

-1

For a coil having L = 2 mH, current flow through it is $$I = {t^2}{e^{ - t}}$$ then, the time at which emf become zero

2 sec

1 sec

4 sec

3 sec

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