NEET 2021 | Motion in a Plane Question 9 | Physics

A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolution.

If this particle were projected with the same speed at an angle '$$\theta$$' to the horizontal, the maximum height attained by it equals 4R. The angle of projection, $$\theta$$, is then given by :

$$\theta = {\sin ^{ - 1}}{\left( {{{2g{T^2}} \over {{\pi ^2}R}}} \right)^{1/2}}$$

$$\theta = {\cos ^{ - 1}}{\left( {{{g{T^2}} \over {{\pi ^2}R}}} \right)^{1/2}}$$

$$\theta = {\cos ^{ - 1}}{\left( {{{{\pi ^2}R} \over {g{T^2}}}} \right)^{1/2}}$$

$$\theta = {\sin ^{ - 1}}{\left( {{{{\pi ^2}R} \over {g{T^2}}}} \right)^{1/2}}$$

NEET 2021

MCQ (Single Correct Answer)

-1

A car starts from rest and accelerates at 5m/s². At t = 4 s, a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at t = 6 s? (Take g = 10 m/s²)

20$$\sqrt 2 $$ m/s, 10 m/s²

20 m/s, 5 m/s²

20 m/s, 0

20$$\sqrt 2 $$ m/s, 0

NEET 2019

MCQ (Single Correct Answer)

-1

When an object is shot from the bottom of a long smooth inclined plane kept at an angle 60^o with horizontal, it can travel a distance x₁ along the plane. But when the inclination is decreased to 30^o and the same object is shot with the same velocity, it can travel x₂ distance. Then x₁ : x₂ will be :

1 : $$\sqrt 2 $$

$$\sqrt 2 $$ : 1

1 : $$\sqrt 3 $$

1 : 2$$\sqrt 3 $$

NEET 2019

MCQ (Single Correct Answer)

-1

A particle moving with velocity $$\overrightarrow V $$ is acted by three forces shown by the vector triangle PQR. The velocity of the particle will : NEET 2019 Physics - Motion in a Plane Question 11 English

NEET 2019 Physics - Motion in a Plane Question 11 English

remain constant

increase

decrease

change according to the smallest force $$\overrightarrow {QR} $$

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