AIPMT 2015 | Oscillations Question 22 | Physics

A particle is executing a simple harmonic motion. Its maximum acceleration is $$\alpha $$ and maximum velocity is $$\beta $$. Them, its time period of vibration will be

$${{{\beta ^2}} \over \alpha }$$

$${{2\pi \beta } \over \alpha }$$

$${{{\beta ^2}} \over {{\alpha ^2}}}$$

$${\alpha \over \beta }$$

AIPMT 2015 Cancelled Paper

MCQ (Single Correct Answer)

-1

A particle is executing SHM along a straight line. Its velocities at distances x₁ and x₂ from the mean position are V₁ and V₂ respectively. Its time period is

$$2\pi \sqrt {{{V_1^2 + V_2^2} \over {x_1^2 + x_2^2}}} $$

$$2\pi \sqrt {{{V_1^2 - V_2^2} \over {x_1^2 - x_2^2}}} $$

$$2\pi \sqrt {{{x_1^2 + x_2^2} \over {V_1^2 + V_2^2}}} $$

$$2\pi \sqrt {{{x_2^2 - x_1^2} \over {V_1^2 - V_2^2}}} $$

AIPMT 2015 Cancelled Paper

MCQ (Single Correct Answer)

-1

When two displacements represented by y₁ = a sin$${\left( {\omega t} \right)}$$ and y₂ = b cos$${\left( {\omega t} \right)}$$ aresuperimposed the motion is

simple harmonic with amplitude $$\sqrt {{a^2} + {b^2}} $$

simple harmonic with amplitude $${{\left( {a + b} \right)} \over 2}$$

not a simple harmonic

simple harmonic with amplitude $${a \over b}$$

AIPMT 2014

MCQ (Single Correct Answer)

-1

The oscillation of a body on a smooth horizontal surface is represented by the equation,
X = A cos$$\left( {\omega t} \right)$$
where X = displacement at time t
$$\omega $$ = frequency of oscillation
Which one of the following graphs shows correctly the variation a with t?
Here a = acceleration at time t
T = time period

AIPMT 2014 Physics - Oscillations Question 46 English Option 1

AIPMT 2014 Physics - Oscillations Question 46 English Option 2

AIPMT 2014 Physics - Oscillations Question 46 English Option 3

AIPMT 2014 Physics - Oscillations Question 46 English Option 4

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