AIPMT 2010 Mains | Alternating Current Question 47 | Physics

A condenser of capacity C is charged to a potential difference of V₁. The plates of th condenser are then connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser reduces to V₂ is

$${\left( {{{C{{\left( {{V_1} - {V_2}} \right)}^2}} \over L}} \right)^{{1 \over 2}}}$$

$${{C\left( {V_1^2 - V_2^2} \right)} \over L}$$

$${{C\left( {V_1^2 + V_2^2} \right)} \over L}$$

$${\left( {{{C\left( {V_1^2 - V_2^2} \right)} \over L}} \right)^{{1 \over 2}}}$$

AIPMT 2010 Prelims

MCQ (Single Correct Answer)

-1

A 220 volt input is supplied to a transformer. The output circuit draws a current of 2.0 ampere at 440 volts. If the efficiency of the transformer is 80%, the current drwn by the primary windings of the transformer is

3.6 ampere

2.8 ampere

2.5 ampere

5.0 ampere

AIPMT 2010 Prelims

MCQ (Single Correct Answer)

-1

In the given circuit the reading of voltmeter V₁ and V₂ are 300 volts each. The reading of the voltmeter V₃ and ammeter A are respectively

AIPMT 2010 Prelims Physics - Alternating Current Question 45 English

150V, 2.2A

220V, 2.2A

220V, 2.0A

100V, 2.0A

AIPMT 2009

MCQ (Single Correct Answer)

-1

Power dissipated in an LCR series circuit connected to an A.C. source of emf $$\varepsilon $$ is

$${{{\varepsilon ^2}\sqrt {{R^2} + {{\left( {L\omega - {1 \over {\omega }}} \right)}^2}} } \over R}$$

$${{{\varepsilon ^2}\sqrt {{R^2} + {{\left( {L\omega - {1 \over {C\omega }}} \right)}^2}} } \over R}$$

$${{{\varepsilon ^2}R} \over {\sqrt {{R^2} + {{\left( {L - {1 \over {C\omega }}} \right)}^2}} }}$$

$${{{\varepsilon ^2}R} \over {\left[ {{R^2} + {{\left( {L\omega - {1 \over {C\omega }}} \right)}^2}} \right]}}$$

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