A pipe open at both ends has a fundamental frequency $f$ in air. The pipe is now dipped vertically in a water drum to half of its length. The fundamental frequency of the air column is now equal to:
The displacement of a travelling wave $$y=C \sin \frac{2 \pi}{\lambda}$$ (at $$-x$$) where $$t$$ is time, $$x$$ is distance and $$\lambda$$ is the wavelength, all in S.I. units. Then the frequency of the wave is
The $$4^{\text {th }}$$ overtone of a closed organ pipe is same as that of $$3^{\text {rd }}$$ overtone of an open pipe. The ratio of the length of the closed pipe to the length of the open pipe is :
The ratio of frequencies of fundamental harmonic produced by an open pipe to that of closed pipe having the same length is
An organ pipe filled with a gas at 27$$^\circ$$C resonates at 400 Hz in its fundamental mode. If it is filled with the same gas at 90$$^\circ$$C, the resonance frequency at the same mode will be
If the initial tension on a stretched string is doubled, then the ratio of the initial and final speeds of a transverse wave along the string is
(Take velocity of sound in air = 330 m s$$-$$1)

(Take gas constant R $$=$$ 8.3 J K$$-$$1 mol$$-$$1)
(Speed of sound in air is 330 m s$$-$$1)
y = 3 sin$${\pi \over 2}$$(50t $$-$$ x),
where x and y are in metres and t is in seconds. The ratio of maximum particle velocity to the wave velocity is
y1 = 4sin600$$\pi $$t and y2 = 5sin608$$\pi $$t
An observer located near these two sources of sound will hear
y1 = $$a$$sin($$\omega $$t + kx + 0.57) m and
y2 = acos($$\omega $$t + kx) m, where x is in meter and t $$in$$ sec. The phase difference between them is
y = Asin($$\omega $$t $$-$$ kx). For what value of the wavelength is the wave velocity equal to the maximum particle velocity ?
y1 = 10$$-$$6 sin[100t + (x/50) + 0.5] m
y2 = 10$$-$$6 cos[100t + (x/50)] m,
where x is expressed in metres and t is exressed in secondss, is approximately.
y $$=$$ 10$$-$$4 sin(100t $$-$$ $${x \over {10}}$$) m. then the velocity of wave will be
x = $$a$$cos($$\omega $$t +$$\delta $$) and y = $$a$$cos($$\omega $$t + $$\alpha $$), where $$\delta $$ = $$\alpha $$ + $${\pi \over 2}$$, the resultant wave represents