A bob is whirled in a horizontal circle by means of a string at an initial speed of $$10 \mathrm{~rpm}$$. If the tension in the string is quadrupled while keeping the radius constant, the new speed is:
Let $$\omega_1, \omega_2$$ and $$\omega_3$$ be the angular speed of the second hand, minute hand and hour hand of a smoothly running analog clock, respectively. If $$x_1, x_2$$ and $$x_3$$ are their respective angular distances in 1 minute then the factor which remains constant $$(k)$$ is
A ball is projected from point A with velocity $$20 \mathrm{~m} \mathrm{~s}^{-1}$$ at an angle $$60^{\circ}$$ to the horizontal direction. At the highest point $$\mathrm{B}$$ of the path (as shown in figure), the velocity $$\mathrm{v} \mathrm{m} \mathrm{s}^{-1}$$ of the ball will be:
A particle is executing uniform circular motion with velocity $$\vec{v}$$ and acceleration $$\vec{a}$$. Which of the following is true?
A bullet is fired from a gun at the speed of $$280 \mathrm{~ms}^{-1}$$ in the direction $$30^{\circ}$$ above the horizontal. The maximum height attained by the bullet is
$$\left(g=9.8 \mathrm{~ms}^{-2}, \sin 30^{\circ}=0.5\right)$$:-
A horizontal bridge is built across a river. A student standing on the bridge throws a small ball vertically upwards with a velocity $$4 \mathrm{~m} \mathrm{~s}^{-1}$$. The ball strikes the water surface after $$4 \mathrm{~s}$$. The height of bridge above water surface is (Take $$g=10 \mathrm{~m} \mathrm{~s}^{-2}$$ )
A cricket ball is thrown by a player at a speed of 20 m/s in a direction 30$$^\circ$$ above the horizontal. The maximum height attained by the ball during its motion is
(g = 10 m/s2)
A ball is projected with a velocity, 10 ms$$-$$1, at an angle of 60$$^\circ$$ with the vertical direction. Its speed at the highest point of its trajectory will be
If this particle were projected with the same speed at an angle '$$\theta$$' to the horizontal, the maximum height attained by it equals 4R. The angle of projection, $$\theta$$, is then given by :


Which of the following is true?
at time t = 2 s and (13 m, 14 m) at time t = 5 s.
Average velocity vector $$\left( {{{\overrightarrow v }_{av}}} \right)$$ from t = 0 to t = 5 s is
(Given g = 9.8 m s$$-$$2)


