A proton is projected with velocity $$\mathbf{v}=2 \hat{\mathbf{i}}$$ in a region where magnetic field $$\mathbf{B}=(\hat{\mathbf{i}}+3 \hat{\mathbf{j}}+4 \hat{\mathbf{k}}) \mu \mathrm{T}$$ and electric field $$\mathbf{E}=10 \hat{\mathbf{i}} \mu \mathrm{V} / \mathrm{m}$$. Then find out the net acceleration of proton

In figure, two parallel infinitely long current carrying wires are shown. If resultant magnetic field at point $$A$$ is zero. Then determine the value of current $$I$$.

Two circular loops having same radius $$(R=10 \mathrm{~cm})$$ and same current $$\frac{7}{2} \mathrm{~A}$$ are placed along same axis as shown. If distance between their centres is $$10 \mathrm{~cm}$$, find net magnetic field at point $$P$$.

If two protons are moving with speed $$v=4.5 \times 10^5 \mathrm{~m} / \mathrm{s}$$ parallel to each other then find the ratio of electrostatic and magnetic force between them

Assertion : Electron moving perpendicular to B will perform circular motion.

Reason : Force by magnetic field is perpendicular to velocity.

Assertion : A charge particle is released from rest in magnetic field then it will move in a circular path.

Reason : Work done by magnetic field is non zero.

A long straight wire, carrying current $$I$$ is bent at its mid-point to form an angle of $$45^{\circ}$$. Induction of magnetic field (in tesla) at point $$P$$, distant $$R$$ from point of bending is equal to

An element $$d l=d x \hat{\mathbf{i}}$$ (where, $$d x=1 \mathrm{~cm}$$ ) is placed at the origin and carries a large current $$i=10 \mathrm{~A}$$. What is the magnetic field on the $$Y$$-axis at a distance of $$0.5 \mathrm{~m}$$ ?

Consider the following figure, a uniform magnetic field of 0.2 T is directed along the positive X-axis. The magnetic flux through top surface of the figure.

Assertion A magnetic field interacts with a moving charge and not with a stationary charge.

Reason A moving charge produce a magnetic field.

A long wire having a semicircular loop of radius r carries a current i as shown in figure. The magnetic induction at the centre O due to entire

A conductor lies along the z-axis at $$-1.5 \leq Z \leq 1.5 \mathrm{~m}$$ and carries a fixed current of 10.0 $$\mathrm{A}$$ in $$-a_z$$ direction as shown in figure for a field $$B=3 \times 10^{-4} e^{-0.2 x} a_y \mathrm{~T}$$, the total power required to move the conductor at constant speed to $$x=2.0 \mathrm{~m}, y=0 \mathrm{~m}$$ in $$5 \times 10^{-3} \mathrm{~s}$$ is (Assume parallel motion along the $$x$$-axis)

Assertion : Cyclotron does not accelerate electron.

Reason : Mass of the electron is very small.