In the given circuit, find charge on capacitor after 1s of opening the switch at $$t=\infty$$.

A capacitor of capacitance $$15 \mu \mathrm{F}$$ having dielectric slab of $$\varepsilon_r=2.5$$, dielectric strength $$30 \mathrm{~MV} / \mathrm{m}$$ and potential difference $$=30 \mathrm{~V}$$. Calculate the area of the plate.

An infinite number of identical capacitors each of capacitance 1 $$\mu$$F are connected as shown in the figure. Then, the equivalent capacitance between A and B is

Assertion A dielectric slab is inserted between plates of an isolated charged capacitor which remain same.

Reason Charge on an isolated system is conserved.

Two capacitors $$C$$ and $$\frac{C}{2}$$ are connected to a battery of $$V$$ volts, as shown below

The work done in charging both the capacitors fully is

A parallel plate capacitor has an electric field of $$10^5 \mathrm{~Vm}^{-1}$$ between the plates. If the charge on the capacitor plates is $$1 \mu \mathrm{C}$$, the force on each capacitor plate is