Electromagnetism
Current Electricity
MCQ (Single Correct Answer)
Moving Charges and Magnetism
MCQ (Single Correct Answer)
Magnetism and Matter
MCQ (Single Correct Answer)
Electromagnetic Induction
MCQ (Single Correct Answer)
Alternating Current
MCQ (Single Correct Answer)
Electromagnetic Waves
MCQ (Single Correct Answer)
Modern Physics
Dual Nature of Radiation
MCQ (Single Correct Answer)
Semiconductor Devices and Logic Gates
MCQ (Single Correct Answer)
Communication Systems
MCQ (Single Correct Answer)
1
COMEDK 2024 Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two point charges $$\mathrm{M}$$ and $$\mathrm{N}$$ having charges $$+q$$ and $$-q$$ respectively are placed at a distance apart. Force acting between them is $$\mathrm{F}$$. If $$30 \%$$ of charge of $$\mathrm{N}$$ is transferred to $$\mathrm{M}$$, then the force between the charges becomes:

A
F
B
$$ \frac{100}{49} F $$
C
$$ \frac{49}{100} F $$
D
$$ \frac{9}{16} F $$
2
COMEDK 2024 Evening Shift
MCQ (Single Correct Answer)
+1
-0

If 216 drops of the same size are charged at $$200 \mathrm{~V}$$ each and they combine to form a bigger drop, the potential of the bigger drop will be

A
2400 V
B
7200 V
C
1200 V
D
8200 V
3
COMEDK 2024 Evening Shift
MCQ (Single Correct Answer)
+1
-0

Three point charges are located on a circular arc at $$\mathrm{A}, \mathrm{B}$$ and $$\mathrm{C}$$ as shown in the figure below. The total electric field at the centre of the $$\operatorname{arc}(\mathrm{C})$$ is

COMEDK 2024 Evening Shift Physics - Electrostatics Question 1 English

A
$$15000 \mathrm{~NC}^{-1}$$
B
$$10000 \mathrm{~N} \mathrm{C}^{-1}$$
C
$$20000 \mathrm{~NC}^{-1}$$
D
$$5000 \mathrm{~NC}^{-1}$$
4
COMEDK 2024 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

A tiny ball of mass $$\mathrm{m}$$ and charge $$\mathrm{q}$$ is suspended from the fixed support using an insulating string of length $$1 \mathrm{~m}$$. The horizontal uniform electric field $$\mathrm{E}$$ is switched on. The angle made by the string with vertical when the ball is in equilibrium is $$45^{\circ}$$. The magnitude of uniform electric field is

A
$$ E=\frac{m g}{q} \quad N C^{-1} $$
B
$$ \mathrm{E}=\frac{\sqrt{2} \mathrm{mg}}{\mathrm{q}} \mathrm{NC}^{-1} $$
C
$$ E=\frac{m g}{\sqrt{2} q} \quad N C^{-1} $$
D
$$ \mathrm{E}=0 \quad \mathrm{NC}^{-1} $$
COMEDK Subjects