VITEEE 2024 | Alternating Current Question 4 | Physics

The primary of a transformer has 400 turns while the secondary has 2000 turns. If the power output from the secondary at 1000 V is 12 kW . The resistance of the primary is $0.2 \Omega$ and that of the secondary is $2 \Omega$. If the efficiency of the transformer is $80 \%$, then the power loss in the primary is

288 W

1125 W

2000 W

725 W

VITEEE 2021

MCQ (Single Correct Answer)

-0

The alternating current in a circuit is given by $$I=50 \sin 314 t$$. The peak value and frequency of the current are

$$I_0=25 \mathrm{~A}$$ and $$f=100 \mathrm{~Hz}$$

$$I_0=50 \mathrm{~A}$$ and $$f=50 \mathrm{~Hz}$$

$$I_0=50 \mathrm{~A}$$ and $$f=100 \mathrm{~Hz}$$

$$I_0=25 \mathrm{~A}$$ and $$f=50 \mathrm{~Hz}$$

VITEEE 2021

MCQ (Single Correct Answer)

-0

A $$50 \mathrm{~Hz}$$ $$\mathrm{AC}$$ signal is applied in a circuit of inductance of $$(1 / \pi) \mathrm{H}$$ and resistance $$2100 \Omega$$. The impedance offered by the circuit is

$$1500 \Omega$$

$$1700 \Omega$$

$$2102 \Omega$$

$$2500 \Omega$$

VITEEE 2021

MCQ (Single Correct Answer)

-0

If the alternating current $$I=I_1 \cos \omega t+ I_2 \sin \omega t$$ then the rms current is given by

$$\frac{I_1+I_2}{\sqrt{2}}$$

$$\frac{\left|I_1+I_2\right|}{\sqrt{2}}$$

$$\sqrt{\left(\frac{I_1^2+I_2^2}{2}\right)}$$

$$\sqrt{\frac{I_1^2+I_2^2}{\sqrt{2}}}$$

Questions Asked from MCQ (Single Correct Answer)

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