COMEDK 2023 Morning Shift | Chemical Kinetics Question 18 | Chemistry

For a reaction, $$2 A+B \longrightarrow$$ products, If concentration of $$B$$ is kept constant and concentration of $$A$$ is doubled then rate of reaction is

doubled

quadrupled

halved

remain same

COMEDK 2023 Evening Shift

MCQ (Single Correct Answer)

-0

A first order reaction proceeds to $$90 \%$$ completion. What will be the approximate time taken for $$90 \%$$ completion in relation to $$t_{1 / 2}$$ of the reaction?

5.02 times of $$\mathrm{t}_{1 / 2}$$

4.54 times of $$\mathrm{t}_{1 / 2}$$

5.66 times of $$\mathrm{t}_{1 / 2}$$

3.32 times of $$\mathrm{t}_{1 / 2}$$

COMEDK 2023 Evening Shift

MCQ (Single Correct Answer)

-0

For a reaction of the type, $$2 \mathrm{X}+\mathrm{Y} \rightarrow \mathrm{A}+\mathrm{B}$$, the following is the data collected:

Experiment	$$\mathrm{[X]}$$	$$\mathrm{[Y]}$$	Initial rate of formation of A
1	0.2	0.2	$$12.0\times10^{-3}$$
2	0.6	0.4	$$\mathrm{14.4\times10^{-2}}$$
3	0.6	0.8	$$5.76\times10^{-1}$$
4.	0.8	0.2	$$\mathrm{4.8\times10^{-2}}$$

What is the overall order of the reaction?

2.5

1.5

COMEDK 2023 Evening Shift

MCQ (Single Correct Answer)

-0

Match the details given in Column I with those given in Column II

S.No.	Column I	S.No.	Column II
A	For complex reactions order is determined by	P	Rate of reaction.
B	For Zero order reaction unit of $\mathrm{k}$ is same as that of	Q	Slope $$=k/2.303$$
C	Mathematical expression which gives relationship between rate of reaction and concentrations of reactants is called	R	Slowest rate determining step.
D	For a first order reaction plot of $$\mathrm{\log \left[R_0\right] /[R]}$$ vs time gives	S	Rate law.

$$ \mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{R} \quad \mathrm{C}=\mathrm{P} \quad \mathrm{D}=\mathrm{Q} $$

$$ \mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{R} \quad \mathrm{C}=\mathrm{Q} \quad \mathrm{D}=\mathrm{P} $$

$$ \mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{P} \quad \mathrm{C}=\mathrm{S} \quad \mathrm{D}=\mathrm{Q} $$

$$ \mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{Q} \quad \mathrm{D}=\mathrm{P} $$

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