COMEDK 2023 Morning Shift | Capacitor Question 6 | Physics

A dielectric of dielectric constant $$K$$ is introduced such that half of its area of a capacitor of capacitance $$C$$ is occupied by it. The new capacity is

$$2 C$$

$$\frac{C}{2}$$

$$\frac{(1+K) C}{2}$$

$$2 C(1+K)$$

COMEDK 2023 Morning Shift

MCQ (Single Correct Answer)

-0

In the figure below, the capacitance of each capacitor is $$3 \mu \mathrm{F}$$. The effective capacitance between $$A$$ and $$B$$ is

COMEDK 2023 Morning Shift Physics - Capacitor Question 6 English

$$\frac{3}{4} \mu \mathrm{F}$$

$$3 \mu \mathrm{F}$$

$$6 \mu \mathrm{F}$$

$$5 \mu \mathrm{F}$$

COMEDK 2023 Morning Shift

MCQ (Single Correct Answer)

-0

If $$C$$ be the capacitance and $$V$$ be the electric potential, then the dimensional formula of $$\mathrm{CV}^2$$ is

$$\left[\mathrm{ML}^2 \mathrm{~T}^{-2} \mathrm{~A}^0\right]$$

$$\left[\mathrm{MLT}^{-2} \mathrm{~A}^{-1}\right]$$

$$\left[\mathrm{M}^0 \mathrm{LT}^{-2} \mathrm{~A}^0\right]$$

$$\left[\mathrm{ML}^{-3} \mathrm{TA}\right]$$

COMEDK 2023 Evening Shift

MCQ (Single Correct Answer)

-0

COMEDK 2023 Evening Shift Physics - Capacitor Question 5 English

In the figure, first the capacitors are fully charged by closing the key $$\mathrm{K}$$. Then after opening the Key a dielectric material with dielectric constant 2 is filled in the space between the plates of both the capacitor. At this state the ratio of the Charge on the capacitor $$C_1$$ to that of $$C_2$$ is:

1 : 1

3 : 2

2 : 1

1 : 2

Previous Next

Questions Asked from MCQ (Single Correct Answer)

COMEDK 2024 Evening Shift (3) COMEDK 2024 Morning Shift (1) COMEDK 2023 Morning Shift (4) COMEDK 2023 Evening Shift (1) COMEDK 2022 (2) COMEDK 2020 (1)

COMEDK Subjects