Thermodynamics
Calculation of Work and Heat
Marks 1Marks 2
Entropy and Irreversibility
Marks 1Marks 2Marks 5
Properties of Pure Substances
Marks 1Marks 2
Basic Concepts and Zeroth Law
Marks 1Marks 2
First Law of Thermodynamics
Marks 1Marks 2Marks 5
Second Law of Thermodynamics
Marks 1Marks 2
1
GATE ME 2011
MCQ (Single Correct Answer)
+1
-0.3
The contents of a well-insulated tank are heated by a resistor of $$23\Omega $$ in which $$10A$$ current is flowing. Consider the tank along with its contents as a thermodynamic system. The work done by the system and the heat transfer to the system are positive. The rates of heat $$(Q),$$ work $$(W)$$ and change in internal energy $$\left( {\Delta U} \right)$$ during the process in $$kW$$ are
A
$$Q=0, W=-2.3,$$ $$\Delta U = + 2.3$$
B
$$Q = + 2.3,\,\,W = 0,\,\,\Delta U = + 2.3$$
C
$$Q = - 2.3,\,\,W = 0,\,\,\Delta U - 2.3$$
D
$$Q = 0\,\,W = + 2.3,\,\,\Delta U - 2.3$$
2
GATE ME 2009
MCQ (Single Correct Answer)
+1
-0.3
A compressor undergoes a reversible, steady flow process. The gas at inlet and outlet of the compressor is designated as state $$1$$ and state $$2$$ respectively. Potential and kinetic energy changes are to be ignored. The following notations are used:
$$v=$$ specific volume and $$P=$$ pressure of the gas.
The specific work required to be supplied to the compressor for this gas compression process is
A
$$\int_1^2 {Pdv} $$
B
$$\int_1^2 {vdP} $$
C
$$v{}_1\left( {{P_2} - {P_1}} \right)$$
D
$$ - {P_2}\left( {{v_1} - {v_2}} \right)$$
3
GATE ME 1996
MCQ (Single Correct Answer)
+1
-0.3
For reversible adiabatic compression in a steady flow process, the work transfer per unit mass is
A
$$\int {Pdv} $$
B
$$\int {vdP} $$
C
$$\int {Tds} $$
D
$$\int {sdT} $$
GATE ME Subjects
Engineering Mechanics
Machine Design
Strength of Materials
Heat Transfer
Production Engineering
Industrial Engineering
Turbo Machinery
Theory of Machines
Engineering Mathematics
Fluid Mechanics
Thermodynamics
General Aptitude