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Signals and Systems
Representation of Continuous Time Signal Fourier Series
Marks 1Marks 2
Fourier Transform
Marks 1Marks 2Marks 5
Continuous Time Signal Laplace Transform
Marks 1Marks 2Marks 5
Discrete Time Signal Fourier Series Fourier Transform
Marks 1Marks 2
Discrete Fourier Transform and Fast Fourier Transform
Marks 1Marks 2
Discrete Time Signal Z Transform
Marks 1Marks 2
Continuous Time Linear Invariant System
Marks 1Marks 2Marks 5
Discrete Time Linear Time Invariant Systems
Marks 1Marks 2Marks 4Marks 5
Transmission of Signal Through Continuous Time LTI Systems
Marks 1Marks 2Marks 5
Sampling
Marks 1Marks 2Marks 4Marks 5
Transmission of Signal Through Discrete Time Lti Systems
Marks 1Marks 2Marks 4
Miscellaneous
Marks 1Marks 2
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1
GATE ECE 2006
MCQ (Single Correct Answer)
+1
-0.3
In the system shown below,
x(t) = (sint)u(t). In steady-state, the response y(t) will be GATE ECE 2006 Signals and Systems - Transmission of Signal Through Continuous Time LTI Systems Question 31 English
A
$${1 \over {\sqrt 2 }}\sin \left( {t - {\pi \over 4}} \right)$$
B
$${1 \over {\sqrt 2 }}\sin \left( {t + {\pi \over 4}} \right)$$
C
$${1 \over {\sqrt 2 }}{e^{ - t}}\sin (t)$$
D
$$\sin (t) - \cos (t)$$
2
GATE ECE 2002
MCQ (Single Correct Answer)
+1
-0.3
A linear phase channel with phase delay $${\tau _p}$$ and group delay $${\tau _g}$$ must have
A
$$\,{\tau _p} = {\tau _g} = $$ constant
B
$${\tau _p}\infty \,\,f\,and\,{\tau _g}\infty \,f$$
C
$${\tau _p}$$ = constant and $${\tau _g}\infty \,f$$
D
$${\tau _p}\infty \,f\,and\,\,{\tau _g}$$ =constant ($$f$$denotes frequency)
3
GATE ECE 1999
MCQ (Single Correct Answer)
+1
-0.3
The input to a channel is a band pass signal. It is obtained by linearly modulating a sinusoidal carrier with a signal- tone signal. The output of the channel due to this input is given by y(t) = (1/100) cos$$(100t - {10^{ - 6}})\,$$ cos$$({10^6}t - 1.56)$$. The group delay $$({t_g})$$ and the phase delay $$({t_p})$$, in seconds, of the channel are
A
$${t_g} = {10^{ - 6}},\,{t_p} = 1.56$$
B
$${t_g} = 1.56,\,\,{t_p} = {10^{ - 6}}$$
C
$${t_g} = \,\,{10^{ - 8}},\,\,{t_p} = 1.56 \times {10^{ - 6}}$$
D
$${t_g} = {10^{ - 8}},\,{t_p} = 1.56$$
4
GATE ECE 1996
MCQ (Single Correct Answer)
+1
-0.3
A rectangular pulse of duration T is applied to a filter matched to this input. The output of the filter is a
A
rectangular pulse of duration T.
B
rectangular pulse of duration 2T.
C
triangular pulse.
D
sine function.
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Questions Asked from Marks 1
GATE ECE 2022 (1) GATE ECE 2016 Set 1 (1) GATE ECE 2014 Set 4 (1) GATE ECE 2013 (2) GATE ECE 2010 (2) GATE ECE 2006 (2) GATE ECE 2002 (1) GATE ECE 1999 (1) GATE ECE 1996 (1)
GATE ECE Subjects
Signals and Systems
Network Theory
Control Systems
Digital Circuits
General Aptitude
Electronic Devices and VLSI
Analog Circuits
Engineering Mathematics
Microprocessors
Communications
Electromagnetics