Signals and Systems
Representation of Continuous Time Signal Fourier Series
Marks 1Marks 2
Fourier Transform
Marks 1Marks 2Marks 5
Continuous Time Signal Laplace Transform
Marks 1Marks 2Marks 5
Discrete Time Signal Fourier Series Fourier Transform
Marks 1Marks 2
Discrete Fourier Transform and Fast Fourier Transform
Marks 1Marks 2
Discrete Time Signal Z Transform
Marks 1Marks 2
Continuous Time Linear Invariant System
Marks 1Marks 2Marks 5
Discrete Time Linear Time Invariant Systems
Marks 1Marks 2Marks 4Marks 5
Transmission of Signal Through Continuous Time LTI Systems
Marks 1Marks 2Marks 5
Transmission of Signal Through Discrete Time Lti Systems
Marks 1Marks 2Marks 4
Miscellaneous
Marks 1Marks 2
1
GATE ECE 2008
MCQ (Single Correct Answer)
+2
-0.6
In the following network (Fig .1), the switch is closed at t = 0- and the sampling starts from t = 0. The sampling frequency is 10 Hz. GATE ECE 2008 Signals and Systems - Discrete Time Signal Z Transform Question 12 English
The expression and the region of convergence of the z-transform of the sampled signal are
A
$${{5z} \over {z - {e^{^{ - 5}}}}},\left| z \right| < {e^{ - 5}}$$
B
$${{5z} \over {z - {e^{^{ - 0.05}}}}},\left| z \right| < {e^{ - 0.05}}$$
C
$${{5z} \over {z - {e^{^{ - 0.05}}}}},\left| z \right| > {e^{ - 0.05}}$$
D
$${{5z} \over {z - {e^{^{ - 5}}}}},\left| z \right| < {e^{ - 5}}$$
2
GATE ECE 2007
MCQ (Single Correct Answer)
+2
-0.6
The z-transform X (z) f a sequence x$$\left[ n \right]$$ is given by = $${{0.5} \over {1 - 2{z^{ - 1}}}}$$ . It is given that the region of convergence of X$$\left[ z \right]$$ includes the unit circle. The value of x$$\left[ 0 \right]$$ is
A
-0.5
B
0
C
0.25
D
0.5
3
GATE ECE 1999
MCQ (Single Correct Answer)
+2
-0.6
The z-transform of a signal is given by c(z)=$${1 \over 4}{{{z^{ - 1}}(1 - {z^{ - 4}})} \over {{{(1 - {z^{ - 1}})}^2}}}$$. Its final value is
A
1/4
B
zero
C
1.0
D
infinity
4
GATE ECE 1990
MCQ (Single Correct Answer)
+2
-0.6
The Z-transform of the following real exponential sequence:
x(nT) = $${a^n}$$, nT $$ \ge $$ 0
=0, nT<0, a> 0
gives us by
A
$${1 \over {1 - {z^{ - 1}}}}; \left| z \right| > 1$$
B
$${1 \over {1 - a{z^{ - 1}}}}; \left| z \right| > a$$
C
1 for all z
D
$${1 \over {1 - a{z^{ - 1}}}}; \left| z \right| < a$$
GATE ECE Subjects
Signals and Systems
Network Theory
Control Systems
Digital Circuits
General Aptitude
Electronic Devices and VLSI
Analog Circuits
Engineering Mathematics
Microprocessors
Communications
Electromagnetics