Analog Circuits
Bipolar Junction Transistor
Marks 1Marks 2Marks 5
Operational Amplifier
Marks 1Marks 2Marks 5Marks 8
Frequency Response
Marks 1Marks 2Marks 5
Feedback Amplifier
Marks 1Marks 2
Power Amplifier
Marks 1Marks 2
1
GATE ECE 2001
MCQ (Single Correct Answer)
+2
-0.6
In the figure assume the Op-Amps to be ideal. The output V0 of the circuit is GATE ECE 2001 Analog Circuits - Operational Amplifier Question 54 English
A
10 $$\cos $$ (100 t)
B
10 $$\int\limits_0^t {\cos \,\,\left( {100\tau } \right)} \,\,d\tau $$ v
C
$${10^{ - 4}}\int\limits_0^t {\cos \,\,\left( {100\tau } \right)} \,\,d\tau $$
D
$${10^{ - 4}}{d \over {dt}}\cos \left( {100t} \right)$$
2
GATE ECE 2001
MCQ (Single Correct Answer)
+2
-0.6
The Inverting Op-Amp shown in the figure, has an Open-loop gain of 100. The closed loop gain $${{{V_o}} \over {{V_s}}}$$ is GATE ECE 2001 Analog Circuits - Operational Amplifier Question 55 English
A
-8
B
-9
C
-10
D
-11
3
GATE ECE 2000
MCQ (Single Correct Answer)
+2
-0.6
If the Op-Amp in the figure has an input offset voltage of 5 mV and an open-loop voltage gain of 10,000, V0 will be GATE ECE 2000 Analog Circuits - Operational Amplifier Question 62 English
A
0 V
B
5 mV
C
+ 15 V (or) - 15V
D
+50 V (or) -50V
4
GATE ECE 1997
MCQ (Single Correct Answer)
+2
-0.6
The output voltage V0 of the circuit shown in the figure is GATE ECE 1997 Analog Circuits - Operational Amplifier Question 61 English
A
-4 V
B
6 V
C
5 V
D
-5.5 V
GATE ECE Subjects
Signals and Systems
Network Theory
Control Systems
Digital Circuits
General Aptitude
Electronic Devices and VLSI
Analog Circuits
Engineering Mathematics
Microprocessors
Communications
Electromagnetics