Power Electronics
Choppers and Commutation Techniques
Marks 1Marks 2Marks 5
Single and Three Phase Rectifier
Marks 1Marks 2Marks 5
Power Semiconductor Devices
Marks 1Marks 2
Ac Voltage Controllers
Marks 1Marks 2Marks 5
1
GATE EE 2003
MCQ (Single Correct Answer)
+2
-0.6
An inverter has a periodic output voltage with the output waveform as shown in figure GATE EE 2003 Power Electronics - Inverters Question 21 English

When the conduction angle $$\alpha = {120^0},$$ the $$rms$$ fundamental component of the output voltage is

A
$$0.78$$ $$V$$
B
$$1.10$$ $$V$$
C
$$0.90$$ $$V$$
D
$$1.27$$ $$V$$
2
GATE EE 2002
MCQ (Single Correct Answer)
+2
-0.6
Fig. $$(a)$$ shows an inverter circuit with a $$dc$$ source voltage $${V_{s}}$$. The semiconductor switches of the inverter are operated in such a manner that the pole voltages $${V_{10}}$$ and $${V_{20}}$$ are as shown in fig.
Fig. $$(b).$$ What is the rms value of the pole-to-pole voltage $${V_{12}}$$: GATE EE 2002 Power Electronics - Inverters Question 22 English 1 GATE EE 2002 Power Electronics - Inverters Question 22 English 2
A
$${{{V_s}\phi } \over {\pi \sqrt 2 }}$$
B
$${V_s}\sqrt {{\phi \over \pi }} $$
C
$${V_s}\sqrt {{\phi \over {2\pi }}} $$
D
$${{{V_s}} \over \pi }$$
3
GATE EE 2001
MCQ (Single Correct Answer)
+2
-0.6
A single - phase full-bridge voltage source inverter feeds a purely inductive load, as shown in figure. when $${T_1},{T_2},\,\,\,\,\,{T_3},{T_4}$$ are power transistors and $${D_1},{D_2},\,{D_3},{D_4}$$ are feedback diodes. The inverter is operated in square-wave mode with a frequency of $$50$$ $$Hz.$$ If the average load current is zero, what is the time duration of conduction of each feedback diode in a cycle? GATE EE 2001 Power Electronics - Inverters Question 23 English
A
$$5\,\,m\,\,\sec $$
B
$$10\,\,m\,\,\sec $$
C
$$20\,\,m\,\,\sec $$
D
$$2.5\,\,m\,\,\sec $$
4
GATE EE 2000
MCQ (Single Correct Answer)
+2
-0.6
A three phase voltage source inverter supplies a purely inductive three phase load. Upon Fourier analysis, the output voltage waveform is found to have an $${h^{th}}$$ order harmonic of magnitude α h times that of the fundamental frequency component $$\left( {{\alpha _h} < 1} \right),$$ the load current would then have an $${h^{th}}$$ order harmonic of magnitude
A
zero
B
$${{\alpha _h}}$$ times the fundamental frequency component
C
$${h{\alpha _h}}$$ times the fundamental frequency component
D
$${\raise0.5ex\hbox{$\scriptstyle {{\alpha _h}}$} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle h$}}$$ times the fundamental frequency component
GATE EE Subjects
Electromagnetic Fields
Signals and Systems
Engineering Mathematics
General Aptitude
Power Electronics
Power System Analysis
Analog Electronics
Control Systems
Digital Electronics
Electrical Machines
Electric Circuits
Electrical and Electronics Measurement