Power Electronics
Choppers and Commutation Techniques
Marks 1Marks 2Marks 5
Single and Three Phase Rectifier
Marks 1Marks 2Marks 5
Power Semiconductor Devices
Marks 1Marks 2
Ac Voltage Controllers
Marks 1Marks 2Marks 5
1
GATE EE 2006
MCQ (Single Correct Answer)
+2
-0.6
A $$3$$ $$-$$ phase fully controlled bridge converter with free wheeling diode is fed from $$400$$ $$V$$, $$50$$ $$Hz$$ $$AC$$ source and is operating at a firing angle of $${60^ \circ }.$$ The load current is assumed constant at $$10A$$ due to high load inductance The input displacement factor $$(IDF)$$ and the input power factor $$(IPF)$$ of the converter will be
A
$$IDF=0.867:IPF=0.828$$
B
$$IDF=0.867:IPF=0.552$$
C
$$IDF=0.5:IPF=0.478$$
D
$$IDF=0.5:IPF=0.318$$
2
GATE EE 2005
MCQ (Single Correct Answer)
+2
-0.6
Consider a phase $$-$$ controlled converter shown in figure The thyristor is fired at an angle $$\alpha $$ in every positive half cycle of the input voltage. If the peak value of the instantaneous output voltage equals $$230$$ $$V,$$ the firing angle $$\alpha $$ is close to GATE EE 2005 Power Electronics - Single and Three Phase Rectifier Question 37 English
A
$${45^ \circ }$$
B
$${135^ \circ }$$
C
$${90^ \circ }$$
D
$${83.6^ \circ }$$
3
GATE EE 2003
MCQ (Single Correct Answer)
+2
-0.6
A phase - controlled half - controlled single - phase converter is shown in figure. The control angle $$\alpha = {30^ \circ }$$ GATE EE 2003 Power Electronics - Single and Three Phase Rectifier Question 38 English

The output $$dc$$ voltage wave shape will be as shown in

A
GATE EE 2003 Power Electronics - Single and Three Phase Rectifier Question 38 English Option 1
B
GATE EE 2003 Power Electronics - Single and Three Phase Rectifier Question 38 English Option 2
C
GATE EE 2003 Power Electronics - Single and Three Phase Rectifier Question 38 English Option 3
D
GATE EE 2003 Power Electronics - Single and Three Phase Rectifier Question 38 English Option 4
4
GATE EE 2002
MCQ (Single Correct Answer)
+2
-0.6
In the single phase diode bridge rectifier shown in fig, the load resistor is
$$R = 50\Omega .$$ The source voltage is
$$V = 200sin\omega t,$$
Where $$\omega = 2\pi \times 50$$ radians per second. The power dissipated in the load resistor $$R$$ is GATE EE 2002 Power Electronics - Single and Three Phase Rectifier Question 39 English
A
$${{3200} \over \pi }W$$
B
$${{400} \over \pi }W$$
C
$$400\,W$$
D
$$800\,W$$
GATE EE Subjects
Electromagnetic Fields
Signals and Systems
Engineering Mathematics
General Aptitude
Power Electronics
Power System Analysis
Analog Electronics
Control Systems
Digital Electronics
Electrical Machines
Electric Circuits
Electrical and Electronics Measurement