GATE EE 2004 | Basics of Control System Question 6 | Control Systems

For a tachometer if $$\theta \left( t \right)$$ is the rotor displacement is radians, $$e\left( t \right)$$ is the output voltage and $${K_t}$$ is the tachometer constant in V/rad/sec, then the transfer function $${{E\left( s \right)} \over {\theta \left( s \right)}},$$ will be

$${K_t}{s^2}$$

$${{{K_t}} \over s}$$

$${{K_t}\,s}$$

$${K_t}$$

GATE EE 2000

MCQ (Single Correct Answer)

-0.3

Feedback control systems are

insensitive to both forward and feedback path parameter changes.

less sensitive to feedback path parameter changes than to forward path parameter changes.

less sensitive to forward-path parameter changes than to feedback path parameter changes.

equally sensitive to forward and feedback path parameter changes.

GATE EE 2000

MCQ (Single Correct Answer)

-0.3

A linear time-invariant system initially at rest, when subjected to a unit-step input, gives a response $$y\left( t \right) = t{e^{ - t}},\,\,t > 0.$$ The transfer function of the system is:

$${1 \over {{{\left( {s + 1} \right)}^2}}}$$

$${1 \over {s{{\left( {s + 1} \right)}^2}}}$$

$${s \over {{{\left( {s + 1} \right)}^2}}}$$

$${1 \over {s\left( {s + 1} \right)}}$$

GATE EE 1995

MCQ (Single Correct Answer)

-0.3

The impulse response of an initially relaxed linear system is $${e^{ - 2t}}u\left( t \right).$$ To produce a response of $${te^{ - 2t}}u\left( t \right),$$ the input must be equal to

$${2e^{ - 2t}}u\left( t \right)$$

$${1 \over 2}{e^{ - 2t}}u\left( t \right)$$

$${e^{ - 2t}}u\left( t \right)$$

$${e^{ - t}}u\left( t \right)$$

Questions Asked from Marks 1

GATE EE 2015 Set 2 (1) GATE EE 2013 (1) GATE EE 2009 (1) GATE EE 2004 (1) GATE EE 2000 (2) GATE EE 1995 (1)

GATE EE Subjects

Electromagnetic Fields

Signals and Systems

Engineering Mathematics

General Aptitude

Power Electronics

Power System Analysis

Analog Electronics

Control Systems

Digital Electronics

Electrical Machines

Electric Circuits

Electrical and Electronics Measurement