Algebra
Sets, Relations and Functions
MCQ (Single Correct Answer)
Quadratic Equations and Inequalities
MCQ (Single Correct Answer)
Sequence And Series
MCQ (Single Correct Answer)
Permutations and Combinations
MCQ (Single Correct Answer)
Three Dimensional Geometry
MCQ (Single Correct Answer)
Trigonometry
Trigonometric Angles and Equations
MCQ (Single Correct Answer)
Inverse Trigonometric Function
MCQ (Single Correct Answer)
Height and Distance
MCQ (Single Correct Answer)
Properties of Triangles
MCQ (Single Correct Answer)
Calculus
Limit, Continuity and Differentiability
MCQ (Single Correct Answer)
Application of Derivatives
MCQ (Single Correct Answer)
Indefinite Integration
MCQ (Single Correct Answer)
Definite Integration
MCQ (Single Correct Answer)
Area Under The Curves
MCQ (Single Correct Answer)
Differential Equations
MCQ (Single Correct Answer)
1
NDA 2017 Paper 2
MCQ (Single Correct Answer)
+2.5
-0.83
The inverse of the function y = 5ln x is
A
$$x = {y^{{1 \over {\ln 5}}}},y > 0$$
B
$$x = {y^{\ln 5}},y > 0$$
C
$$x = {y^{{1 \over {\ln 5}}}},y < 0$$
D
$$x = {5^{\ln x}},y > 0$$
2
NDA 2017 Paper 2
MCQ (Single Correct Answer)
+2.5
-0.83
The function f(x) = | x | $$-$$ x3 is
A
odd
B
even
C
both even and odd
D
neither even nor odd
3
NDA 2017 Paper 2
MCQ (Single Correct Answer)
+2.5
-0.83
If x is any real number, then $${{{x^2}} \over {1 + {x^4}}}$$ belongs to which one of the following intervals?
A
(0, 1)
B
$$\left[ {0,{1 \over 2}} \right]$$
C
$$\left( {0,{1 \over 2}} \right)$$
D
[0, 1]
4
NDA 2017 Paper 2
MCQ (Single Correct Answer)
+2.5
-0.83
If $$f(x) = {x \over 2} - 1$$, then on the interval [0, $$\pi$$] which one of the following is correct?
A
tan[f(x)], where [ . ] is the greatest integer function, and $${1 \over {f(x)}}$$ are both continuous.
B
tan[f(x)], where [ . ] is the greatest integer function, and f$$-$$1(x) are both continuous.
C
tan[f(x)], where [ . ] is the greatest integer function, and $${1 \over {f(x)}}$$ are both discontinuous.
D
tan[f(x)], where [ . ] is the greatest integer function is discontinuous but $${1 \over {f(x)}}$$ is continuous