Consider the following statements:

1. $\frac{n!}{3!}$ is divisible by 6, where n > 3

2. $\frac{n!}{3!}+3 $ is divisible by 7, where n > 3

Which of the above statements is/are correct?

In how many ways can a team of 5 players be selected out of 9 players so as to exclude two particular players ?

Let S = {2, 3, 4, 5, 6, 7, 9}. How many different 3-digit numbers (with all digits different) from S can be made which are less than 500?

If C(n, 4), C(n, 5) and C(n, 6) are in AP, then what is the value of n?