Three digits are chosen at random from 1, 2, 3, 4, 5, 6, 7, 8 and 9 without repeating any digit. What is the probability that the product is odd?

Two events A and B are such that P (not B) = 0.8, P (A $$\cup$$ B) = 0.5 and P (A / B) = 0.4. Then, P(A) is equal to

If mean and variance of a binomial variate X are 2 and 1 respectively, then the probability that X takes a value greater than 1, is

Seven unbiased coins are tossed 128 times. In how many throws would you find at least three heads?